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CGP EDU Academic Team
Published on: August 13, 2026
Let P be the relation defined on the set of all real numbers such that P = {(a, b) : sec 2 a-tan 2 b =1}. Then P is
Text Solution
Verified by ExpertsThe correct answer is:
D
an equivalence relation
P = {(a, b):sec 2 a-tan 2 b = 1}
sec 2 a-tan 2 b = 1
sec 2 a=1+tan 2 b
sec 2 a=sec 2 b
|seca| = |secb|
sec 2 a -tan 2 b = 1
1+ tan 2 a - sec 2 b + 1 = 1
sec 2 b - tan 2 a = 1
Hence, it is Symmetric.
If | sec a| = | sec b| and |sec b | = |secc| then |sec a |= |secc| 
transitive
So it is an equivalence relation.
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